Termination w.r.t. Q of the given QTRS could be disproven:

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(b(a(x1))) → b(b(b(x1)))
b(a(b(x1))) → a(b(a(x1)))

Q is empty.

(1) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:

a b a a b b → a b a a b b

a b a a b b → a b a a b b
by OverlapClosure OC 3

a b a a b b → b a b a b b
by OverlapClosure OC 3

a b a a b b → b b a b b b
by OverlapClosure OC 2

a b a → b b b
by original rule (OC 1)

b a b b → a b b b
by OverlapClosure OC 2

b a b → a b a
by original rule (OC 1)

b a b → b b b
by OverlapClosure OC 2

b a b → a b a
by original rule (OC 1)

a b a → b b b
by original rule (OC 1)

b a b → a b a
by original rule (OC 1)

b a b → a b a
by original rule (OC 1)

(2) NO